(n-7)(4n^2+5n-4)=

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Solution for (n-7)(4n^2+5n-4)= equation:


Simplifying
(n + -7)(4n2 + 5n + -4) = 0

Reorder the terms:
(-7 + n)(4n2 + 5n + -4) = 0

Reorder the terms:
(-7 + n)(-4 + 5n + 4n2) = 0

Multiply (-7 + n) * (-4 + 5n + 4n2)
(-7(-4 + 5n + 4n2) + n(-4 + 5n + 4n2)) = 0
((-4 * -7 + 5n * -7 + 4n2 * -7) + n(-4 + 5n + 4n2)) = 0
((28 + -35n + -28n2) + n(-4 + 5n + 4n2)) = 0
(28 + -35n + -28n2 + (-4 * n + 5n * n + 4n2 * n)) = 0
(28 + -35n + -28n2 + (-4n + 5n2 + 4n3)) = 0

Reorder the terms:
(28 + -35n + -4n + -28n2 + 5n2 + 4n3) = 0

Combine like terms: -35n + -4n = -39n
(28 + -39n + -28n2 + 5n2 + 4n3) = 0

Combine like terms: -28n2 + 5n2 = -23n2
(28 + -39n + -23n2 + 4n3) = 0

Solving
28 + -39n + -23n2 + 4n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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